ML Aggarwal CBSE Solutions Class 6 Math First Chapter Knowing Our Numbers Exercise 1.4
(1) Round off each of the following numbers to their nearest tens:
(i) 77 = 80
(ii) 903 = 900
(iii) 1205 = 1200
(iv) 999 = 1000
(2) Estimate each of the following numbers to their nearest hundreds:
(i) 1246 = 1200
(ii) 32057 = 32100
(iv) 53961 = 54000
(v) 555555 = 555600
(3) Estimate each of the following numbers to their nearest thousands:
(i) 5706 = 6000
(ii) 378 = 1000
(iii) 47599 = 48000
(iv ) 1,09736 = 110000
(4) Give a rough estimate (by rounding off to nearest hundreds) and also a closer estimate (by rounding off to nearest tens):
(i) 439 + 334 + 4317
= 400 + 300 + 4300 (Nearest 100)
= 5000
439 + 334 + 4317
= 440 + 330 + 4320 (Nearest 10)
= 5090
(ii) 8325 – 491
= 8300 – 500 (Nearest 100)
= 7800
8325 – 491
= 8320 – 490 (Nearest 10)
= 7830
(iii) 108734 – 47599
= 108700 – 47600 (Nearest 100)
= 61100
108734 – 47599
= 108730 – 47600 (Nearest 10)
= 61130
(iv) 4,89,348 – 48,365
= 489300 – 48400 (Nearest 100)
= 440900
4,89,348 – 48,365
= 489350 – 48360 (Nearest 10)
= 440990
(5) Estimate each of the following by rounding off each number nearest to its greatest place:
(i) 730 + 998
= 700 + 1000
= 1700
(ii) 5290 + 17986
= 5000 + 20000
= 25000
(iii) 796 – 314
= 800 – 300
= 500
(iv) 28,292 – 21496
= 30000 – 20000
= 10000
(6) Estimate the following products by rounding off each of its factors nearest to its greatest place:
(i) 578 x 161
= 600 x 200
= 120000
(ii) 9650 x 27
= 10000 x 30
= 300000
(7) Estimate the following products by rounding off each of its factors nearest to its hundreds place.
(i) 5281 x 3491
= 5300 x 3500
= 18,550,000
(ii) 1387 x 888
= 1400 x 900
= 1,260,000
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